WAEC Physics Questions and Answers 2019 | waec 2019 Physics Objective


WAEC Physics Questions and Answers 2021 | WAEC 2021 Physics Obj and Theory

WAEC physics questions and answers 2021 is out and has been released for science students who are writing the examination soon. Like our nature which has always been to give you the examination questions before time and this we have done it for 2021 waec physics questions and answers.

WAEC Physics Questions

Our examination questions on geography and that of Literature in English was genuine and till date, we are still receiving a lot of appreciation for making the questions available for them and that is why move to source for waec physics past questions and answers download pdf this questions and answers comprises of the questions and answers for both obj, theory/Essay in the waec physics question 2021.

From what we have noticed, the questions comprising of the waec physics questions and answers 2021 is drawn from the 2009 to 2014 physics past questions and answers pdf and so was the same thin applicable in the waec past questions on physics practical.

If you study the waec physics past questions pdf extensively, there is a possibility of having to see the 2021 waec  physics questions and answers for May/June candidates. You can download the waec past questions and answers download (pdf) for Physics and other subjects and prepare effectively for the examination.

It is one thing to study the waec past questions on physics and another thing to know the right questions which will appear in your examination. And this waec physics questions and answers 2021 will help you to pass the WAEC examination on physics without stress.

waec physics questions and answers 2021 was released by an insider form the West African examination council and that is why we have gotten the questions and update it on our site. Below, we will show you the 2021 physics waec question for both objective and theory. The Physics questions are arrange numerically for easy comprehension.

Nature and Structure of waec physics questions | physics obj and theory

The nature of Waec Questions for both Obj and Theory differs from the Questions on practical. From the waec physics practical past questions, we can see that the practical questions have different questions which are distinct from the WAEC theory and Objective, so don’t mistake waec physics practical for theory questions or objective questions.


Consequently, the from the physics past question and from our waec physics questions and answers 2020, we can see that the waec 2020 physics theory questions has 50 questions while the Essay questions consist of 6 questions on the waec 2020 physics theory question.


This is the composition of all the waec 2021 physics obj and theory for thosw who are wondering about the nature of the examination, you have to have less worry and know that you will answer about 50 questions in Obj and about six questions for the theory.


According to the Waec  timetable, the waec physics examination will commence on Tuesday 10th April. The Objective examination will start by 8.30 and will end by 10.00 while the Essay will start by 10.00 am and will end by 11.15 am.


WAEC Physics Questions and Answers 2021 |


Every year, more than 3 million candidates registers for the West African Senior School Certificate Examination (WASSCE) and everyone expect to make a good grades in the examination, hence the need to help student  waec May/June 2021 physics questions.


Our questions are updated for all candidates who will write the waec May/June physics 2021 examination. Not only have we made questions available, but we have also made available waec physics answer 2021 which those providing you with questions can’t do. Our answers was provided by an authority who is an examiner and knows how to answer Physics questions even that of physics 2021 waec questions.


Looking at the waec past questions and answers download pdf, you will realized that the examiners for Physics are always careful not to make any mistake in the questions set, but always looking for workings in the exams.


To solve the waec physics questions, you will have to take your time in making sure that all workings are shown in your work and you should also endeavor to solve in steps.


If you have been solving the waec past questions and answers on Chemistry and Physics, you will agree with me that the waec physics questions 2021 needs a bit reason and you will be able to confirm the questions by soling them yourself.


Waec 2021 Questions and Answers | Obj


Without much ado we will bring to you the waec physics questions and answers 2021 for Obj. For the sake of time ad the lack of it we would have also presented the 2021 Obj Questions, but in order to save time and bring the answers before the exams start, we have decided to make available only the answers to the objective questions.


The answers are verified from a reliable source and a waec teach/examiner who has marked WAEC script for many years.


Here are the Obj answers














2021 Physics Question Theory/Essay  | waec Physics questions and answers



Strain can be defined as the ratio of extension per unit length





Let original length=L

Final length=2L





(i) Silicon Dioxide

(ii) Silica Powder

(iii) Germanium Tetrachloride



(i) Ferromagnetic material

(ii) Diamgentic material


(iii) Pamangentic material


(4a) An intrinsic semiconductor is an undoped semiconductor that is a pure semiconductor without any significant dopant species present. (4b) The P Type semiconductor is a type of semiconductor that carries a positive charge, while the N type semiconductor carries a negative charge .



Range = u²Sin2tita/g

At maximum range

Sin2tita = 1

2tita =sin^-1(1)

2tita = 90dgrees

Tita = 90/2 = 45degree


Maximum height reached = u²sin²tita/2g









Given constant = 2.9×10^-3mk

Temperature = 57degreeC = (57+273)k = 330k

Using landamaxT = constant

landamaxT330 = 2.9×10^-3

landamax = 2.9×10^-3/330

landamax = 8.788×10^-6m

The speed of electromagnetic wave, v = 3×10^8m/s

Using V = f landa

f = v/landa





LASER stands for Light Amplification by Stimulated Emission of Radiation.



Laser is a device that generates an intense beam of coherent monochromatic light or other electromagnetic radiation by stimulated emission of photons from excited atoms or molecules


(9ai) (i) Nature of the Substance (ii) Medium of transmission (9aii) (i)State or phase of the substance (i.e Solid, Liquid or gas). (ii)Temperature of the medium (9b) (i) Temperature (ii) Specific hear capacity of the body (9c) The statement means that the amount of hear energy required to change 1kg of liquid mercury to gaseous mercury without change in temperature is 2.72*10^5Kg^-1 9d(i) PleasenNote (π) means Change in temperature Q Q=MCπQ V^2/R * t=MCπQ (220)^2*4*60/35=M*4200*(100-28) 33,885.7=302400m M=33,885.7/302400 M=1.098kg 9d(ii) V^2/R *t=MLv (220)^2 *5 *60/35=0.3*Lv 414857.14=0.3Lv Lv=414857.14/0.3 Lv=1382857.13Jkg^-1

(10a) Diffraction is the ability of waves to bend around obstacles in their path (10bi) Critical angle is the highest angle of incidence in a denser medium when angle of refraction in the less dense mediumis 90 degrees (10bii) Critical angle=90-44=46degrees The refractive index of the glass is obtained as follows The refractive index(n)=sini/sinr=sin46/sin90=0.7193/1 =0.7193 (10ci) fo=200Hz f1=3v/4l =>closed pipe f1=v/l=>open pipe but 3fo=f1=>closed pipe 3*200=f1=>f1=600Hz Also f1=2fo=>open pipe 2fo=600 fo=600/2=300Hz (10cii) v=330m/s L=? fo=200Hz fo=v/4l =>200=330/4l 800l=330 l=330/800 l=0.4124m (10ciii) fo=v/2l fo=300Hz v=330m/s 300=330/2l l=330/600 l=0.55m


(12a) This is defined as the amount of energy that must be supplied to a nucleus to completely separate it’s nuclear particles (nucleons)



(i) They have short wavelength and high frequency.

(ii) They are highly penetrating.

(iii) They travel in straight lines.

(iv) They don’t require material medium for their propagation.



-It is used in production of electricity.

-It is used to study and detect charges in genetic engineering.

-It is used in agriculture.

-It is used in treatment of cancer.



E = hf-hfo

but f = v/landa

E= v/landa.h – wo

Where wo = hfo = work function

f= frequency

landa = wavelength


hf = hfo – E

f = hfo – E/h

f = wo – E/h

Recall; that v = f landa

Therefore f = v/landa = 3×10^8/4.5×10-7

=3/4.5 × 10^8+7


f = 6.6×10^14Hz



E = hf

=6.6×10^-34 × 6.6×10^14Hz




Energy of the photoelectron E = hf – vo

=Energy of incident electron – work function

=4.356×10^-19J – 3.0×10^-19J



These are the complete Physics questions and answers for waec 2021 and this questions will be of help to you. Having to study this questions before time will help you pass Waec 2021. It is our advise that you do not copy these questions to the exams hall to avoid being caught. Better still the best way to pass exams is my memorizing the answers for both Obj and Essay.


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